The figure below is a cross-sectional view of a coaxial cable. The center conduc
ID: 1361109 • Letter: T
Question
The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I1 = 1.20 A out of the page and the current in the outer conductor is I2 = 2.98 A into the page. Assuming the distance d = 1.00 mm, answer the following.
(a) Determine the magnitude and direction of the magnetic field at point a.
_____ µT
---Select---
to the left
to the right
upward
downward
into the page
out of the page
(b) Determine the magnitude and direction of the magnetic field at point b.
________ µT
---Select---
to the left
to the right
upward
downward
into the page
out of the page
_____ µT
direction---Select---
to the left
to the right
upward
downward
into the page
out of the page
Explanation / Answer
At Point A
B = uo*Ia/ 2*pi*ra
B = (4*pi*10^-7 * 1.2)/ (2*pi*1*10^-3)
B = 2.4 * 10^-4 T
B = 240 uT
Direction = To the top , in +ve Y Direction.
At point B
B = uo*IB/ 2*pi*r
B = (4*pi*10^-7 * (2.98 -1.2))/ (2*pi*3*10^-3)
B = 1.187 * 10^-4 T
B = 118.7 uT
Direction = To the bottom , in -ve Y Direction.
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