1)An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to e

Question

1)An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.29 x 105 m/s to a final velocity of 2.07 x 106 m/s while traveling a distance of 0.0622 m. The electron's acceleration is due to two electric forces parallel to the x axis: Upper FSubscript 1 Baseline Overscript right-arrow EndScripts = 7.13 x 10-17 N, and Upper FSubscript 2 Baseline Overscript right-arrow EndScripts, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force Upper FSubscript 2 Baseline Overscript right-arrow EndScripts.

Explanation / Answer

here,

mass of electron , me = 9.1 * 10^-31 kg

initial velocity , v0 = 7.29 * 10^5 m/s

final velocity , v = 2.07 * 10^6 m/s

distance travelled , s = 0.0622 m

let the accelration be a

using third equation of motion

v^2 - v0^2 = 2 * a * s

(2.07 * 10^6)^2 - (7.29 * 10^5)^2 = 2 * a * 0.0622

a = 3.02 * 10^13 m/s^2

(a)

the net force acting on the electron Fnet = m*a

Fnet = 2.75 * 10^-17 N

the net force acting on the electron is 2.75 * 10^-17 N

(b)

F1 - F2 = Fnet

7.13 * 10-17 N - F2 = 2.75 * 10^-17 N

F2 = 4.38 * 10^-17 N

the electric force F2 is 4.38 * 10^-17 N

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