You are helping your best friend move into a new apartment A heavy crate of mass

Question

You are helping your best friend move into a new apartment A heavy crate of mass 10kg is at rest on the living room carpet. The coefficient of static friction mu, between the crate and the carpet is 0. 20. Suppose that you were to exert a constant force with F = 9. 8 N on the crate, as shown in the diagram. While von are pushing on the crate, is the magnitude of the frictional force greater, less than, or equal to the magnitude F of the force that you are applying? Explain. While you are wishing on the crate, does the crate move? Does the crate move to the left ox to the right? Does the crate move with constant speed, increasing speed, or decreasing speed? Explain. If there is insufficient information, specify what information you need to answer the question. If not: Explain why nor While you are Pushing on the crate, u the magnitude of the frictional force greater than, less than, or equal to the quantity mu, mg? Explain your reasoning. Suppose that the crate from Question 4 were at rest on a different horizontal surface. The coefficents of static and kinetic friction (mu and mu_s) between the crate and the new surface are unknown. In tins ease, when a horizontal force of the magnitude F-9. 8N is applied to the crate, the crate moves. While the crate is moving (and the force is still being applied), does the crate move with constant speed, increasing speed, or decreasing speed? Explain. If there is insufficient information, specify what information you need to answer the question. While the crate is moving (and the force is till being applied), is the magnitude of the frictional force greater than, less than, or equal to the magnitude of the applied force F? Explain your reasoning.

Explanation / Answer

applied force F = 9.8 N

maximum static frictional force f = us*m*g = 0.2*10*9.8 = 19.6 N

(a)

magnitude of frictional force fs is greater than the applied force F

(b)

here the applied force is less than the frictional force

the crate will not move

(c)

equal to us*m*g

(5)

increasing speed

if F > fs the crate moves

as the crate start to move the frictional force fk is less than fs

therefore Fnet = F-fk

Fnet = m*a

F-fk = m*a

a = positive

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