A bungee jumper of mass m is tied to a cord of length L . She falls from a bridg

Question

A bungee jumper of mass m is tied to a cord of length L. She falls from a bridge that is a height H above the river below. The cord stretches such that she comes to a stop when she is only at a height D above the river. What is the magnitude of the the impulse exerted on the bungee jumper while the cord stretched? Enter your symbolic answer as a function of m, H, L, D, and g, plus physical constants such as 1.0 or 0.5. As with all symbolic answers, do not ever include units or unit conversion factors.

Explanation / Answer

when the jumper is L m below the bridge, his/her velocity is
v = (2gh) = (2*9.81*L)
the momentum = m*v = m* (2*9.81*L) kgm/s
at the end of the stretching phase the momentum is = 0.

So the impulse = change of momentum is = m* (2*9.81*L) kgm/s.

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