Gloria got an idea for a Chick-fil-a stunt, but things have gone horrible wrong,

ID: 1364787 • Letter: G

Question

Gloria got an idea for a Chick-fil-a stunt, but things have gone horrible wrong, and she's stuck.

Use these values to answer the questions about Gloria.

rA = 7 m

rB = 2.42 m

mG = 230 kg

g = 9.81 m/s2

(The bar is made of etherium, which has no mass and is infinitely strong.)

1) What is the value of the tension in the rope directly holding Gloria?

TA = _____?N

2) What is the value of the torque (about the fulcrum) produced by the tension TA?

?A = ____? N-m (clockwise)

3) What is the value the tension in the rope at the opposite end from Gloria?

TB =____? N

4) Gloria calculated that the upward (normal) force required by the fulcrum is 7325 N.

Was she correct?

Please show work.

1) TA = mG*g

= 230*9.8

= 2254 N

2)Torque due to TA = TA*rA*sin(90)

= 2254*7*1

= 15778 N.m

3) As the bar is in equilibrium, net force and net torque acting on the bar must be equal to zero.

Net torque about fucrum = 0

TB*rB - TA*rA = 0 (here clockwise torque is negative ans counterclockwise torque is positive)

TB = TA*rA/rB

= 15778/2.42

= 6519.8 N

4) Let F is the uoward force exerted by the fulcrum on the bar.

Net force on the bar = 0

F - TB - TA = 0

F = TA + TB

= 2254 + 6519.8

= 8773.8 N

She is not correct.

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