Billiard ball A of mass m A = 0.121 kg moving with speed v A = 2.80 m/s strikes
ID: 1365088 • Letter: B
Question
Billiard ball A of mass mA = 0.121 kg moving with speedvA = 2.80 m/s strikes ball B, initially at rest, of mass mB= 0.138 kg . As a result of the collision, ball A is deflected off at an angle of A = 30.0 with a speed vA = 2.10 m/s,and ball B moves with a speed vB at an angle of B to original direction of motion of ball A.
Part A
Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the x direction.
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Part B
Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the y direction.
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Correct
Part C
Solve these equations for the angle, B, of ball B after the collision. Do not assume the collision is elastic.
Express your answer to three significant figures and include the appropriate units.
0.808ms
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Enter your answer using dimensions of plane angle.
Part D
Solve these equations for the speed, vB, of ball B after the collision. Do not assume the collision is elastic.
Express your answer to three significant figures and include the appropriate units.
Billiard ball A of mass mA = 0.121 kg moving with speedvA = 2.80 m/s strikes ball B, initially at rest, of mass mB= 0.138 kg . As a result of the collision, ball A is deflected off at an angle of A = 30.0 with a speed vA = 2.10 m/s,and ball B moves with a speed vB at an angle of B to original direction of motion of ball A.
Part A
Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the x direction.
Taking the axis to be the original direction of motion of ball , choose the correct equation expressing the conservation of momentum for the components in the direction. mAvA=mAvAcosA+mBvBcosB 0=mAvAsinAmBvBsinB 0=(mAvA+mBvB)sinB mAvA=mAvAcosAmBvBsinBSubmitMy AnswersGive Up
Correct
Part B
Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the y direction.
Taking the axis to be the original direction of motion of ball , choose the correct equation expressing the conservation of momentum for the components in the direction. mAvA=mAvAcosA+mBvBcosB 0=mAvAsinAmBvBsinB 0=(mAvA+mBvB)sinB mAvA=mAvAcosAmBvBsinBSubmitMy AnswersGive Up
Correct
Part C
Solve these equations for the angle, B, of ball B after the collision. Do not assume the collision is elastic.
Express your answer to three significant figures and include the appropriate units.
B =0.808ms
SubmitMy AnswersGive Up
Incorrect; Try Again; 5 attempts remaining
Enter your answer using dimensions of plane angle.
Part D
Solve these equations for the speed, vB, of ball B after the collision. Do not assume the collision is elastic.
Express your answer to three significant figures and include the appropriate units.
vB =Explanation / Answer
given,
mA = 0.121 kg
vA = 2.80 m/s
mB= 0.138 kg
A = 30.0
vA = 2.10 m/s
by conservation of momentum
initial horizontal momentum = final horizontal momentum
mAvA=mAvAcosA+mBvBcosB
0.121 * 2.8 = 0.121 * 2.1 * cos(30) + 0.138 * vBcosB
initial vertical momentum = final vertical momentum
0=mAvAsinAmBvBsinB
0=0.121 * 2.1 * sin(30) 0.138 * vBsinB
on solving we'll get
v'B = 1.26015 m/s
B = 0.730588
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