A hardworking ant must supply 0.00955 N to pull a small piece of fruit at consta

Question

A hardworking ant must supply 0.00955 N to pull a small piece of fruit at constant velocity over a distance of 8.80 cm up a small hill to the entrance of the colony. If the coefficient of kinetic friction between the piece of fruit and the 25.0° sloped hill is 0.480, calculate the work done by the ant by pulling the piece of fruit up the hill.

Answer in Joules

Use the work-energy theorem to calculate the mass of the piece of fruit in grams. (The acceleration due to gravity is 9.81 m/s2.)

Answer in Grams

Explanation / Answer

Here ,

force applied by the ant , F = 0.00955 N

work done by the ant = 0.00955 * 0.088

work done by the ant = 8.404 *10^-4 J

the work done by the ant is 8.404 *10^-4 J

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let the mass of the fruit is m

Using work energy theorum

net work done = change in energy

8.404 *10^-4 - 0.480 * m * 9.8 * cos(25)* 0.088 = m * 9.8 * 0.088 * sin(25)

solving for m

m = 0.00114 Kg = 1.14 gm

the mass of grain is 1.14 gm

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