During a neighborhood baseball game in a vacant lot, a particularly wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.143-kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 14.7 m / s, shatters the glass as it passes through, and leaves the window at 11.1 m / s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball?

a)The direction of the ball's motion

b)Opposite the direction of the ball's motion

c)Neither of these

Calculate the magnitude of this impulse (a positive number).

The ball is in contact with the glass for 0.0108 s as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).

Note: This question has three answers

Explanation / Answer

Since there is no change in direction , the impulse must be in exactly the opposite direction to the velocity of the baseball.
Impulse = change in momentum = (11.1 - 14.7)m/s * 0.145kg = -0.5148 N.s
(negative sign indicates opposite direction to velocity)

Magnitude of impulse = 0.5148 N.s
Impulse = F.dt
so average force

F = 0.5148 N.s / 10,01108 s = 47.66 N

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