An electric turntable 0.800 m in diameter is rotating about a fixed axis with an

Question

An electric turntable 0.800 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.260 rev/s . The angular acceleration is 0.880 rev/s2 .

Part A.) Compute the angular velocity after a time of 0.202 s . answer w=0.438 rev/s

Part B.) Through how many revolutions has the blade turned in this time interval? answer is N=7.05*10^-2 rev

Part C.) What is the tangential speed of a point on the tip of the blade at time t = 0.202 s ? answer is v=1.10 m/s

Part D.) What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t = 0.202 s ?

I got 3.02 buts its not correct

Explanation / Answer

D)

angular acceleration = 0.88 rev/s^2 = 0.88*2*pi rad/s^2 = 5.53 rad/s^2

r = 0.8/2 = 0.4 m

a = r* angular acceleration

= 0.4 * 5.53

= 2.2 m/s^2

Answer: 2.2 m/s^2

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