ooooo AT&T; 21:32 449610 capa6.phy.ohiou.edu Bullet fired into rotating rod Due,

Question

ooooo AT&T; 21:32 449610 capa6.phy.ohiou.edu Bullet fired into rotating rod Due, 28.2015, 21:00:00 (EDT) | D Axis 60° A uniform thin rod of length 0.60 m and mass 6.0 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is a rest when a 3.0-g bullet traveling in the rotation plane is fired into one end of the rod. As viewed from above, the bullet's path makes an angle of 60° with the rod (see the figure). If the bullet lodges in the rod and the angular velocity of the rod is 10.0 rad/s immediately after the collision, what is the bullet's speed just before impact? 1.039m/s

Explanation / Answer

Use law of conservation of angular momentum

Li = Lf

m( v x r) = Lf rod + Lf bullet .

mvrsinq= [ Irod*wf + Inullet]wf

mvrsinq= ((Mx2/12) +(m(x/2)2)]* wf

m= mass of bullet = 0.003kg ,

M= mass of rod = 6.0kg

x= length of rod = 0.6m

wf=10rad/s

v= velocity of bullet =….?

0.003*v*0.3*sin60 = [(6*0.6^2)/12 +(0.003*0.3^2)]*10

v= 2.3*10^3 m/s

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