Finding Mass of Hanging object on inclined Pulley system. I know how to solve th

Question

Finding Mass of Hanging object on inclined Pulley system. I know how to solve this is both masses are given and I'm told to find accelration but or if it gave m1 and find mass2 but I have no idea how my teache found this. The answer is 1.6 kg. I converted ,72 radiosn to 41.25 degreesHow? The answer is the hanging mass is 1.6 kg.

a= 3.1 m/s M2 M1 5 Two maes are coupled with an ideal pulle andoeM2 s 10 kg and on an inclined plane 5) Two masses are coupled with an ideal pulley and rope. M2 is 10 kg and on an inclined plane at an angle = 0.72 Radians. The second mass is suspended from the pulley and has a mass, MI. The masses are accelerating as shown in the diagram at 3.1 m/st. The coefficient of friction is = 0.06. Find MI. (6 pts)

Explanation / Answer

theta = 0.72 radians

= 0.72*360/(2*pi)

= 41.25 degrees

Let T is the tension in the string.

Net force acting on M1, Fnet1 = T - M1*g

M1*a = T - M1*g

T = M1*a + M1*g ---(1)

Net force acting on M2,

Fnet2 = M2*g*sin(theta) - T - mue_k*M2*g*cos(theta)

M2*a = M2*g*sin(theta) - T - mue_k*M2*g*cos(theta)

T = M2*g*sin(theta) - mue_k*M2*g*cos(theta) - M2*a

= 10*9.8*sin(41.25) - 0.06*10*9.8*cos(41.25) - 10*3.1

= 29.2 N

substitute T in equation 1

T = M1*(a+g)

M1 = T/(a+g)

= 29.1/(3.1+9.8)

= 2.26 kg

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