When you jump, you start by crouching down a bit, which lowers your center of ma
ID: 1367088 • Letter: W
Question
When you jump, you start by crouching down a bit, which lowers your center of mass to a distance d 40 cm below where it normally is. You then exert a downward contact force on the ground equal to about 2.5 times your weight (mg); we may assume that this force is constant while it acts. After your center of mass rises past its usual location, you leave the ground with an initial velocity v, and you reach a maximum height h. Ignore air resistance for this problem.
c) What is the total work done by gravity on your body during the time while you are pushing against the ground? What is the total work done by the normal force on your body during the time while you are pushing against the ground?
d) Find the initial kinetic energy of your body as it leaves the ground using the WKE theorem and your answers to part c). What is your takeoff speed v? How high will you jump (h)?
Explanation / Answer
When you jump, you start by crouching down a bit, which lowers your center of ma
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