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http:// pling IN Summer Undergraduate Resea Shop H & Gard pts 67 62 Copyright 20 2015 Sapling d/ibis/ php?id 2223592 es Neuromuscular function after P Pandora Internet Radio Listen... Nebraska Wesleyan Universi... x If The Distance From A To CI Muscular System ry App Sh Suggested S Web S ESPN Disney 0/27/2015 11 55 PM CA 7.6/10 10/26/2015 03:53 PM o Assignment Information Gradebook Print Period T Available From: 0/2 015 09:00 AM 10/27/2015 11:55 PM Due Date: Map Points Possible: 10 A block is attached to a horizontal spring; beginning with the spring compressed and the block at rest, the block is released into motion on a frictionless tabletop. The block has mass m 4.88 kg, and the initial Grade Category: Exit HW s 5.00 cm. After relea the spring begins to p ush block back toward th equilibrium Compl position at x 0 cm. Th e graph shows the spring force on he block (in N) versus the position of the block pti (in cm) relative to equilibrium. Use the graph to answer the following questions. Homework (soln after due Policies: How much work is done by the spring in deduct MC) pushing the block from its nitial position a x -5.00 cm to x 2.97 cm? You can check your answers he d date. 0.097 F (N You can keep trying to answer each question until you get it right or give up peed of the block when es x- 2.97 cm? of 0.199 For multiple-choice questions, the penalty f ch What is the maximum speed of the block? incorrect According to the Work-Energy Th m, the block ses ki gy wh the sp eTextbook ork on it. The maximum speed will therefore occur re any negative work done, 0.705 o Help With This Topi O Web Help & Videos OP Previous Try Again Next E 52 privacy policy tact 5.08 PM

Explanation / Answer

Here ,

from the graph ,

F = k * x

k = 6/.05 = 120 N/m

Now ,

work done by spring = - 0.5 * k * (xf^2 - xi^2)

work done by spring = 0.5 * 120 * (0.05^2 - 0.0297^2)

work done by spring = 0.097 J
--------------------------

for the speed is v

Using work energy theorum

0.5 * 4.88 * v^2 = 0.097

v =0.199 m/s

-----------------

Now , for mximum speed is v

Using conservation of energy

0.5 * 4.88 * v^2 = 0.5 * 120 * 0.05^2

v = 0.25 m/s

the maximum speed of the block is 0.25 m/s

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