http://www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=2223934 w e Muscular

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http://www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=2223934 w e Muscular System | P Pandora Radio-Listen to Free | Human muscles-Google slide -Nebraska Wesleyan Universi Summer Undergraduate Resea.. s Neuromuscular function after × H Shop Home & Garden - P... a Amazon.com - Online Sh...eBayPlay Free GamesSuggestd SitesWeb Slice Gallery Apple DisneyESN Yahoo! O 10/27/2015 1 1:55 PM 7.5/10 10/27/2015 05:17 PM Print Calculator |4 Periodic Table Assignment Information Available From 10/23/2015 09:00 AM Due Date Points Possible 10 Grade Category: Exit H Description: Policies: deduct MC) Attempts Score Gradebook 50 10/27/2015 11:55 PM 2 100 Map UNIVERSITY PHYSICS Philip R.Kestch Davld L. Tatiek this question has been customized by Nathaniel Cunningham at Nebraska Wesleyan University A 20.0-g object is placed against the free end of a spring (with spring constant k equal to 25.0 N/m) that is compressed 10.0 cm. Once released, the object slides (wh friction) across the tabletop and eventually lands 0.61 m from the edge of the table on the floor, as shown in the figure. The tabletop is 1.00 m above the floor level. Homework (soln after due, You can check your answers You can view solutions after the due date You can keep trying to answer each question until you get it right or give up You lose 5% of the points available to each answer in your question for each incorrect What is the speed of the block at the moment it leaves the tabletop? Assume air drag is negligible 1.00 m Number 0.61 m 1.35 m/s attempt at that answer How much mechanical en block-spring system during the sliding motion? Give energy lost as a positive value is lost from the For multiple-choice questions, the penalty depends on the number of choices available. Number eTextbook Help With This Topic Web Help & Videos 18.225 Incorrect. Previous Try AgainNext Exit Explanation Copyright© 2011-2015 Sapling Learning, Inc.-152 about us careers partners privacy policy terms of use contact ushelp 9:19 PM 10/27/2015

Explanation / Answer

given,

mass = 20 gmk = 25 N/m

x = 10 cm

distance = 0.61 m

height = 1 m

time it'll take to reach ground t

s = 0.5 * at^2

1 = 0.5 * 9.8 * t^2

t = 0.452 sec

speed = distance / time

speed = 0.61 / 0.452

speed of the block at the moment it leaves the tabletop = 1.349 m/s

enery lost = 0.5 * kx^2 - 0.5 * mv^2

enery lost = 0.5 * 25 * 0.1^2 - 0.5 * 0.02 * 1.349^2

enery lost = 0.1068 J

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