Objectives: Understand the 1-dimensional kinematics. Exercise a falling body pro

Question

Objectives: Understand the 1-dimensional kinematics. Exercise a falling body problem is a constant acceleration problem. Exercise formulas for constant acceleration case with the gravitational acceleration. A rock is thrown vertically upward from ground level at time t = 0, At t = 1.5 s it passes the top of a tall tower, and 1.0 s later it reaches its maximum height. How long does the rock take to reach its maximum height? tmax = 1.5 s + 1.0 s = 2.5 s. Estimate the initial velocity of the rock when it is released from ground level. What is the height of the tower? What is the maximum height the rock call reach?

Explanation / Answer

(2) tmax = 2.5 s

v =u+at

0 =u -gt

u =gtmax = 9.8*2.5

u= 24.5 m/s

(3) t =1.5 s

s =ut+(1/2)at2

s = 24.5*1.5 -(1/2)9.8*(1.5)2

s = 36.75- 11.025

Height of building s = 25.725 m

(4) v2- u2 =2as

-u2 =-2gh

h =u2/2g = (24.5)2/2*9.8

h = 30.625 m

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