Two skaters with masses of 63 kg and 52 kg , respectively, stand 8.0 m apart, ea
ID: 1368762 • Letter: T
Question
Two skaters with masses of 63 kg and 52 kg , respectively, stand 8.0 m apart, each holding one end of a piece of rope.
A) If they pull themselves along the rope until they meet, how far does each skater travel? (Neglect friction.) Express your answers using two significant figures separated by a comma.
B) If only the 52 kg skater pulls along the rope until she meets her friend (who just holds onto the rope), how far does each skater travel? Express your answers using two significant figures separated by a comma.
Explanation / Answer
here
in both the cases they will meet at the centre of gravity of the system.
let that be at a distance of x from the 63 kg skater.
so :
63 * x = (8 - x) * 52
thus x= 3.61 m
thus the 63 kg skater travels 3.61 m and the 52 kg skater travels 8 - 3.61 = 4.39 m in both the cases.
b)
if only one person pulls, you get the same result.
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