a uniform rod of mass1 = 4.7 kg and legth 80 cm lies horizontal frictionless tab
ID: 1371570 • Letter: A
Question
a uniform rod of mass1 = 4.7 kg and legth 80 cm lies horizontal frictionless table, with a vertical frictionless axle passing through a point P, located 25cm from center of mass of the rod. Also a particle of mass 2 = 1.2 kg is attached to the rod 5 cm from the far end.A. Find the moment of inertia of the rod only about point P.
The system is initially rotating counter clock wise about P at 6.40 rad/s, at the instant rod is aligned with the y axis, an explosive charge fires m2 at speed 8.2 m/s at angle 35 with respect to x axis. Find angular momentum of particle at moment just after explosion as measured with respect to the axle at P
C, find final angular velocity of rod after explosion a uniform rod of mass1 = 4.7 kg and legth 80 cm lies horizontal frictionless table, with a vertical frictionless axle passing through a point P, located 25cm from center of mass of the rod. Also a particle of mass 2 = 1.2 kg is attached to the rod 5 cm from the far end.
A. Find the moment of inertia of the rod only about point P.
The system is initially rotating counter clock wise about P at 6.40 rad/s, at the instant rod is aligned with the y axis, an explosive charge fires m2 at speed 8.2 m/s at angle 35 with respect to x axis. Find angular momentum of particle at moment just after explosion as measured with respect to the axle at P
C, find final angular velocity of rod after explosion a uniform rod of mass1 = 4.7 kg and legth 80 cm lies horizontal frictionless table, with a vertical frictionless axle passing through a point P, located 25cm from center of mass of the rod. Also a particle of mass 2 = 1.2 kg is attached to the rod 5 cm from the far end.
A. Find the moment of inertia of the rod only about point P.
The system is initially rotating counter clock wise about P at 6.40 rad/s, at the instant rod is aligned with the y axis, an explosive charge fires m2 at speed 8.2 m/s at angle 35 with respect to x axis. Find angular momentum of particle at moment just after explosion as measured with respect to the axle at P
C, find final angular velocity of rod after explosion
Explanation / Answer
A) Use parallel axis theorem,
I = Icm + m*d^2
= m*L^2/12 + m*d^2
= 4.7*0.8^2/12 + 4.7*0.25^2
= 0.54 kg.m^2
B) angular momentum of the particle = m*v*R*sin(35)
= 1.2*8.2*0.5*sin(55)
= 4.03 kg.m^2/s
C) Apply coonservation of momentum
Li = Lf
( 0.54 + 1.2*0.5^2)*6.4 = 4.03 + 0.54*w
==> w = ( ( 0.54 + 1.2*0.5^2)*6.4 - 4.03)/0.54
= 2.5 rad/s
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