4. The volume of a 1.50 mole of an Ideal gas at 20 degree C expands isothermally

Question

4. The volume of a 1.50 mole of an Ideal gas at 20 degree C expands isothermally from 3.0x10'^-3 m^3 to 18.0x10^-3 m^3. Determine the work done by the gas. 5. Oxygen gas of mass 40 g is compressed adiabatically from STP to a pressure of 505 kPa. Determine the new volume of the gas. (R= 8.31 J/mol K; molar mass of oxygen = 32 g/mol; y = 1.40; standard pressure = 101 kPa) 6. A vessel contain 5 x10^-3m^3 of air at pressure 202 kPa and temperature 300 K. If the gas is compressed adiabatically with the pressure is doubled, determine

Explanation / Answer

Mass of Oxygen = 14 gm

And STP condition that is ....

P (Pressure) = 505 kpa

R (gas constant) = 8.314 Lkpa/k mol

T (absolute temperature) = 27. k

V (volume) = ?

n (mole) = mass / molar mass = 40/32 = 1.25 mol

Formula...

PV = nRT

505 * V = 1.25 * 8.314 * 273

505 * V = 2837.1525

V = 2837.1525/505

V = 5.618Lts.

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