please make sure you provide the Matlab code, and I will rate Write a MATLAB fun

Question

please make sure you provide the Matlab code, and I will rate

Write a MATLAB function named [ABCD] - abcdm (z, y, Lngt) to evaluate and return the ABCD transmission matrix for a medium length transmission line where z is the per phase series impedance per unit length, y is the shunt admittance per unit length, and Lngt is the line length. Then, write a program that uses the above function and computes the receiving end quantities, voltage regulation, and the line efficiency when sending end quantities are specified The program should prompt for the following quantities: . The sending end line- to line voltage magnitude in kV. . The sending end voltage phase angle in degrees. . The three phase sending end real power in MW . The three phase sending end reactive power in Mvar Use your program to obtain the solution of the following case: A three phase transmission line has a per phase series impedance of z-0.03 + j 0.4 ? per km and a per phase shunt admittance of y-j4.0 x 106 siemens per km. The line is 125 km long. Obtain the ABCD transmission matrix. Determine the receiving end quantities, voltage regulation, and the line efficiency when the line is sending 407 MW, 7.833 Mvar at 350 kV Deliverables: (a)MATLAB m file along with the desired inputs and outputs (b)Hand calculation to prove that MATLAB program is working.

Explanation / Answer

The following function named abcdm returns the line ABCD constants
function [ABCD] = abcdm(z, y, Lngt);
Z = z*Lngt;
Y = y*Lngt;
A = 1 + Z*Y/2; B = Z;
C = Y*(1+ Z*Y/4); D = A;
ABCD =[A B; C D];

The following program saved as matlab1.m computes the receiving end quantities from the specified sending end quantities

MATLAB CODE

z=input('Line series impedance per phase per unit length z=');
y=input(line shunt admittance per phase per unit length y=');
Lngt = input('iransmission line length =');
ABCD = abcdm(z, y,Lngt)
VL_s=input('Sending end line-to-line voltage magnitude in kV=');
AngV_s=input('Sending end voltage phase angle in degree =');
P_s =input(Three-phase sending end real power in MW');
Q_s =input(Three-phase sending end reactive power in Mvar ');
S_s = P_s + j*Q_s; % MVA
AngV_srd = AngV_s*pi/180; % Radian
V_s = VLs/scirt(3)*(cos(AngV_srd) + j*sin(AngV_srd)); %kV
I_s = conj(S_s)/(3*conj(V_s)); % kA
IL_s= abs(l_s)*1000; AngV_srd = angle(l_s);
Angl_s = Angl_srd*180/pi;
Vl_r = inv(ABCD)*[V_s; I_s];
V_r = VI_r(1); VL_r = sqrt(3)*abs(V_r);
AngV_rrd = angle(V_r); AngV_r =AngVird*180/pi;

l_r = Vl_r(21: IL_r = abs(1_0*1000: AnaI_rd =angle(I_r);
Angl_r = Angl_rd*180/pi;
S_r = 3*V_r*conj(l_r); P_r = real(S_r);
Q_r = imag(S_r); A = abs(ABCD(1,1));
Reg = (VL_s/A - VL_r)/VL_r*100;
Eff = P_r/P_s*100;
fprintf('Sending end line-to-line voltage =%g KV n', VL_s)
fprintf('Sending end voltage phase angle =%g Degree n',AngV_s)
fprintf('Sending end real power = %g MW ', P_s)
fprintf('Sending end reactive Power = %g Mvar ', Q_s)
fprintf('Sending end current = %g A n', IL_s)
fprintf('Sending end current phase angle=%g Degree ',Angl_s)
fprintf('receiving end line-to-line voltage = %g KV n',VL_r)
fprintf('receiving end voltage phase angle=%g Degree n',AngV_r)
fprintf('receiving end real power = %g MW ', P_r)
fprintf('receiving end reactive Power = %g Mvar ', Q_r)
fprintf('receiving end current = %g A n',
fprintf('receiving end current phase angle=%g Degree ',Angl_r)
fprintf(Voltage regulation = %g percent ',Reg)
fprintf('Transmission efficiency = %g percent ',Eff)

typing matlab1.m at the MATLAB prompt result in

Line series impedance per phase per unit length z = 0.03+j*0.4
Line shunt admittance per phase per unit length y = j*4.0e-6
Transmission line length = 125

ABCD =
0.9875+ 0.0009i 3.7500+50.0000i
0.0000+ 0.0005i 0.9875+ 0.0009i

Sending end line-to-line voltage magnitude in kV = 350
Sending end voltage phase angle in degree = 0
Three-phase sending end real power in MW 407
Three-phase sending end reactive power in Mvar 7.883
Sending end line-to-line voltage = 350 kV
Sending end voltage phase angle = 0
Degree Sending end real power = 407 MW
Sending end reactive Power = 7.883 Mvar
Sending end current = 671.502 A
Sending end current phase angle = -1.1096 Degree
Receiving end line-to-line voltage = 345.003 kV
Receiving end voltage phase angle = -9.63278 Degree
Receiving end real power = 401.884 MW
Receiving end reactive Power = 0.0475969 Mvar
Receiving end current = 672.539 A
Receiving end current phase angle = -9.63957 Degree
Voltage regulation = 2.73265 percent
Transmission efficiency = 98.7429 percent

Note: As per your requirement i answered only matlab code.

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.