The long, thin wire shown is in a region of constant magnetic field. The wire ca
ID: 1372950 • Letter: T
Question
The long, thin wire shown is in a region of constant magnetic field. The wire carries a current of 6.2 A and is oriented at an angle of 7.5
The long, thin wire shown is in a region of constant magnetic field. The wire carries a current of 6.2 A and is oriented at an angle of 7.5 A degree to the direction of the magnetic field. (a) If the magnetic force exerted on this wire per meter is 0.027 N, what is the magnitude of the magnetic field? ______ mT (b) At what angle will the force exerted on the wire per meter be equal to 0.015 N? _____ A degree (Does less magnetic force mean the wire makes a smaller or larger angle with the B field?)Explanation / Answer
The magnetic force on a length "L" of current "i" ,when the current makes angle "theta" with the B-field is;
F = iLBSin(theta)
So the Force per unit Length is;
(F/L) = iBSin(theta)
a) (2.7x10^-2) = (6.2)(B)Sin(7.5)
B = .0333 T
b) Now use this "B" in the same basic formula to find the angle for the new force per unit length;
.015 = (6.2)(.0333)Sin(theta)
Sin(theta) = .0726
theta = 4.16 deg
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