The magnitude of the net force exerted in the x direction on a 3.35-kg particle
ID: 1372986 • Letter: T
Question
The magnitude of the net force exerted in the x direction on a 3.35-kg particle varies in time as shown in the figure below.
(a) Find the impulse of the force over the 5.00-s time interval.
(b) Find the final velocity the particle attains if it is originally at rest.
(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
The magnitude of the net force exerted in the x direction on a 3.35-kg particle varies in time as shown in the figure below. i m/s. (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. (a) Find the impulse of the force over the 5.00-s time interval. (b) Find the final velocity the particle attains if it is originally at rest. (c) Find its final velocity if its original velocity is -3.30Explanation / Answer
A.
The impulse is the area under the F-t curve, which is an area of a trapezoid.
Thus,
J = 12.0 N*s [ANSWER, PART A]
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B.
As
J = pf - pi
and pi = 0, then
J = pf = 12 kg*m/s
As
pf = m vf --> vf = pf / m
Then
vf = 3.58 m/s [ANSWER, PART B]
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As
J = m(vf - vi)
--> vf = J/m + vi
and vi = -3.30 m/s,
vf = 0.282 i^ m/s [ANSWER, PART C]
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The average force is
Fave = J/t
Thus,
Fave = 2.4 N [ANSWER, PART D]
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