A. Find the force due to a 0.65T magnetic Field directed to the south on a strai

Question

A. Find the force due to a 0.65T magnetic Field directed to the south on a straight wire segment of length 2.75m carrying a current of 3.00A to the east. B. Compute the force on a proton moving to the south at a speed of 3.50x10^6m/s due to a downward directed magnetic field of intensity 4.50x10^-5T A. Find the force due to a 0.65T magnetic Field directed to the south on a straight wire segment of length 2.75m carrying a current of 3.00A to the east. B. Compute the force on a proton moving to the south at a speed of 3.50x10^6m/s due to a downward directed magnetic field of intensity 4.50x10^-5T B. Compute the force on a proton moving to the south at a speed of 3.50x10^6m/s due to a downward directed magnetic field of intensity 4.50x10^-5T

Explanation / Answer

part A:

magnetic force of charged particle palced in uniorm magnteic field is given by

F = iLB sin theta

where i is current

L is length

B = magnetic field

theta is the angle betweeen L and B

so here we apply

so

F = 3 * 2.75 * 0.65 * sin 90

F = 5.36 N

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magnetic force of charged particle palced in uniorm magnteic field is given by

F = qvB sin theta

where q = charge

v = velcotiy of charge

B = magnetic field

theta is the angle betweeen v   and B

so here we apply

so F   = 1.6 e-19 * 3.5 e 6 * 4.5 e -5

F = 2.52 *10^-17 N

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