Trampoline vibration? When a 55-kg boy sits at ron a trampoline, it sags 0.10 m

Question

Trampoline vibration? When a 55-kg boy sits at ron a trampoline, it sags 0.10 m at the center. I only need help with Part C. Please only give me an equation or steps as to how to do the problem.

Part A: What is the effective spring constant for the trampoline? 5390 N/m

Part B: The trampoline is pulled downward an extra 0.050 m by a strap sewed under the center of the trampoline. When the strap is released, what is the energy of the trampoline? 6.75 J

Part C: What is the frequency of the trampoline?

Explanation / Answer

Note that

f = (1/ [2 pi]) sqrt(k/m)

Thus, as k = 5390 N/m, m = 55 kg,

f = 1.58 Hz   [ANSWER, PART C]

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