Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(a) Assuming that the mass of the cannon and its carriage is 4,500 kg, find the

ID: 1373169 • Letter: #

Question

(a) Assuming that the mass of the cannon and its carriage is 4,500 kg, find the recoil speed of the cannon.
m/s

(b) Determine the maximum extension of the spring.
m

(c) Find the maximum force the spring exerts on the carriage.
N

(d) Consider the system consisting of the cannon, carriage, and projectile. Is the momentum of this system conserved during the firing?

YesNo    


Why or why not?

A cannon is rigidly attached to a carriage, which can move along horizontal rails but is connected to a post by a large spring, initially unstretched and with force constant k = 1.95 a) Assuming that the mass of the cannon and its carriage is 4,500 kg, find the recoil speed of the cannon. m/s (b) Determine the maximum extension of the spring. m (c) Find the maximum force the spring exerts on the carriage. N (d) Consider the system consisting of the cannon, carriage, and projectile. Is the momentum of this system conserved during the firing? YesNo Why or why not? x 10^4 N/m, as shown in the figure below. The cannon fires a 230-kg projectile at a velocity of 125 m/s directed 45.0 A degree above the horizontal.

Explanation / Answer

We can apply cons of momentum to the cannon and the projectile in the horizontal direction. the initial momentum is 0, and the final is mvcos(45) - MV
so mvcos(45) - MV =0, or V = m/M vcos(45)

b) now we apply cons of energy to the cannon and the spring. Ei = 1/2MV^2 V from answer a
Ef = 0 + 1/2kx^2 where x is the extension of the spring

Ei = Ef
1/2MV^2 = 1/2 kx^2, solve for x

c) The maximum force exerted by the spring occurs at the max displacment |F| = k x use x from b

d) We can consider the momentum for the cannon, carriage and projectile conserved in the x direction since there are no external forces. However, since there is a normal force and gravity in the y direction, the momentum in the y direction is not conserved.