I have a low pressure heating chamber to sublimate fullerene particles onto a pi

Question

I have a low pressure heating chamber to sublimate fullerene particles onto a piece of glass. This heater requires up to 50 A of current. The line voltage in the wall is 120 V (RMS voltage). The breaker for the socket limits the current to 10 A out of the wall. I have a transformer that has the following wiring internally.

a) Which of the secondary windings might be capable of supplying the 50A of current?

b) What are the number of winding in each of the secondary windings if the primary winding is 240 turns?

c) When I connect the heating element to Winding

I have a low pressure heating chamber to sublimate fullerene particles onto a piece of glass. This heater requires up to 50 A of current. The line voltage in the wall is 120 V (RMS voltage). The breaker for the socket limits the current to 10 A out of the wall. I have a transformer that has the following wiring internally. a) Which of the secondary windings might be capable of supplying the 50A of current? b) What are the number of winding in each of the secondary windings if the primary winding is 240 turns? c) When I connect the heating element to Winding ??C?? I get a current flow of 65 Amps. How much current is flowing in the input power cord? d) When 50 A is passing through the heater I measure a resistance of 0.1 Ohms. How many windings do I want to have on secondary ??C?? in order to get close to this value? {I am going to have to add or remove some windings to get the proper voltage}

Explanation / Answer

a)

From transformer turns ratio

NP/NS=VP/VS=IS/IP

Secondary Current of each winding

=>IS=IP*(VP/Vs)

For Winding A

IS=10*(120/50) =24 A

For Winding B

IS=10*(120/30) =40 A

For Winding C

IS=10*(120/10) =120 A

So secondary Winding C is capable of supplying 50 A of current .

b)

Number of secondary windings

NS=NP*(VS/VP)

For Winding A

Ns=240*(50/120) =100 turns

For WInding B

Ns=240*(30/120) =60 turns

For winding C

Ns=240*(10/120)=20 turns

c)

Current in primary

IP=Is*(Vs/VP) =65*(50/120)

IP=27.08 A

d)

Windings should be same

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