At time t = 0 s, a wheel has an angular displacement of zero radians and an angu

Question

At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +22 rad/s. The wheel has a constant acceleration of -0.51 rad/s2. In this situation, the time at which the angular displacement is +73 rad and decreasing is closest to:

At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +22 rad/s. The wheel has a constant acceleration of -0.51 rad/s2. In this situation, the time at which the angular displacement is +73 rad and decreasing is closest to:

Explanation / Answer

apply ang displacement theta = Wt - 0.5 Alpha t^2

where W = 22 rad/s

Alpha    A = -0.51 rad/s^2

theta = 73 rad

so

the eqn is   73-22t -(0.5* 0.51 * t^2) = 0

so 0.255t^2 +22t - 73 = 0

sovling for t

t = -(22) +- sqrt(22^2 +(4* 0.255 * 73)/(2*0.255)

t = -22 +- 23.63)/(2*0.255)

t = 3.2 secs

option 1 or 2 it is as both are 3 secs

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