A single slit of width d = 0.08 mm is illuminated by light of two wavelengths, l

Question

A single slit of width d = 0.08 mm is illuminated by light of two wavelengths, l = 441 nm and l = 663 nm. The diffraction pattern appears on a screen 1.38 m away.

(a) Calculate the width of the central bright fringe for each wavelength.

d441= ? m

d663= ? m

A single slit of width d = 0.08 mm is illuminated by light of two wavelengths, l = 441 nm and l = 663 nm. The diffraction pattern appears on a screen 1.38 m away. (a) Calculate the width of the central bright fringe for each wavelength. d441= ? m d663= ? m

Explanation / Answer

a) we know, Central bright fringe width = 2*lamda*R/d

d(441) = lamda*R/d

= 2*441*10^-9*1.38/(0.08*10^-3)

= 1.52*10^-2 m or 1.52 cm

d(663) = 2*lamda*R/d

= 2*663*10^-9*1.38/(0.08*10^-3)

= 2.28*10^-2 m or 2.28 cm

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