Exercise 29.23 In the figure (Figure 1) a conducting rod of length L = 34.0cm mo

Question

Exercise 29.23

In the figure (Figure 1) a conducting rod of length L = 34.0cm moves in a magnetic field B?  of magnitude 0.500Tdirected into the plane of the figure. The rod moves with speed v = 5.50m/s in the direction shown.

Part A

What is the potential difference between the ends of the rod?

Part C

When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod?

Part F

What is the potential difference across the rod if it moves parallel to ab?

Part G

What is the potential difference across the rod if it moves directly out of the page?

Exercise 29.23 In the figure (Figure 1) a conducting rod of length L = 34.0cm moves in a magnetic field B? of magnitude 0.500Tdirected into the plane of the figure. The rod moves with speed v = 5.50m/s in the direction shown. Part A What is the potential difference between the ends of the rod? Part C When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod? Part F What is the potential difference across the rod if it moves parallel to ab? Part G What is the potential difference across the rod if it moves directly out of the page?

Explanation / Answer

the potential is given as:

B*l*v*sin(theta)

where theta is anle between veloicty vector and magnetic field vector

part A:

here theta=90 degres

potential=0.935 volts

part C:
there wont be any static charge as the rod is conducting

part F:
the angle will still remain 90 degrees hence potnetial will remain the same.

part G:

angle will be 0 degree and emf=0

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