Ray 1 of light in medium A (see the figure (Figure 1) ) strikes the surface at 5

Question

Ray 1 of light in medium A (see the figure (Figure 1) ) strikes the surface at 51.0? with respect to the normal.

Part A

Show that the angle of refraction of ray 1 with respect to the normal in medium B is 35.8?.

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Part B

Now suppose that ray 2 is the reverse of ray 1, so that it strikes the surface at 35.8? with the normal in B. Show that ray 2 will come out in A at 51.0? with the normal. In other words, show that rays 1 and 2follow the same path, except reversed from each other.

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Ray 1 of light in medium A (see the figure (Figure 1) ) strikes the surface at 51.0? with respect to the normal. Part A Show that the angle of refraction of ray 1 with respect to the normal in medium B is 35.8?. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining SubmitMy AnswersGive Up Part B Now suppose that ray 2 is the reverse of ray 1, so that it strikes the surface at 35.8? with the normal in B. Show that ray 2 will come out in A at 51.0? with the normal. In other words, show that rays 1 and 2follow the same path, except reversed from each other. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining SubmitMy AnswersGive Up

Explanation / Answer

We know that

From the snell's law

nAsintheta1 =nBsintheta2

a)

For the first case

1.25sin(51) =1.66sintheta2

Therefore sintheta2 =(1.25/1.66)sin(51) =0.5852

Now theta2 =sin-1(0.5852) =35.817degrees

When a ray moving from the rarer medium to denser medium the ray bends towards the normal.

b)

Now again from the snells law

nBsintheta1 =nAsintheta2

1.66sin(35.8) =(1.25)sintheta2

sintheta2 =(1.66/1,25)sin(35.8) =0.7768

Then theta2 =sin-1(0.7768) =50.97degree =51 degrees

Now the ray is moving from nB denser medium to the nA rarer medium,the ray bends away from the normal.

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