1511:55 PMO 50/1004/7/2015 11:11 AM Print CalculatorPeriodic Table of 6 leaming

Question

1511:55 PMO 50/1004/7/2015 11:11 AM Print CalculatorPeriodic Table of 6 leaming An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2160 x103 seconds (about 25 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 225.0x 10m and the planet has a radius of 3.50 x 10 m, calculate the moon's radial acceleration. Number m/s ici, acheck Answer e Ned 8E.. O Prevous @Gy,Ae lint

Explanation / Answer

Here ,

for the moon , time period = 2160 *10^3 s

angular speed , w = 2*pi/T

w = 6.282/(2160 *10^3)

w = 2.91 *10^-6 rad/s

NOw, radial acceleration = w^2*r

radial acceleration = ( 2.91 *10^-6 )^2 * 225 *10^8

radial acceleration = 0.19 m/s^2

the radial acceleration of the moon is 0.19 m/s^2

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