During the Cold War, American submarines operated as \"lone wolves\" at extreme

Question

During the Cold War, American submarines operated as "lone wolves" at extreme ocean depths for many months at a time. Ordinary radio signals are greatly attenuated at such depths, making communication with the submarines difficult. One way suggested to communicate with the submarines was a program the Navy called Seafarer that used extremely low frequency waves. If the Seafarer transmitter broadcast at 83 Hz, what would the transmitter's quarter wavelength antenna have to be in order to receive the signal?

answer in km

Explanation / Answer

apply, c = f*lamda

==> lamda = c/f

= 3*10^8/83

= 3614457.8 m

quarter wavelength = lamda/4

= 3614457.8/4

= 903614.45 m

= 903.6 km

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