A bunch of fake Indians are on a ship docked in Boston Harbor and want to push a
ID: 1377777 • Letter: A
Question
A bunch of fake Indians are on a ship docked in Boston Harbor and want to push all the Crates of tea over the edge of the ship, into the water. They set up a ramp to do it. The ramp is 10.0 m long, and its end is propped up so that it is 5.00 m above the deck. The dock or the ship is 15.0 m above the surface of the water. Each crate of tea has it mass of 50.0 kg. They push the crates of tea all the way up the 10.0 m ramp, two at a time, starting from the bottom. The static coefficient of friction between a crate and the ramp is 0.350 and the kinetic coefficient of friction between a crate and the ramp is 0.250, a. If the Indians push with a combined force, F= 1,100 N parallel to the ramp, what is the horizontal distance from the edge of the ramp, d, that the crates hit the water? b. On one of their runs up the ramp, the top crate falls off half way up the ramp. The Indians continue to push the remaining crate the rest of the way up the ramp with the same combined force of F = 1,100 N parallel to the ramp. What is the horizontal distance from the edge of the plank, d, that the single remaining crate now hits the water? On another run up the ramp with a pair of crates, half the Indians fall off the ramp half way up and drown. Without pausing, the remaining Indians push the two crates the rest of the way up the ramp. Now what is the horizontal distance from the edge of the plank, d, that the crates hit the water? (Assume that the remaining Indians can push with half the force, or 550 N.) The remaining Indians now push another pair of crates up the ramp. Now what is the horizontal distance from the edge of the plank, d, that the crates hit the water?Explanation / Answer
https://www.dropbox.com/s/966wf7nj9nf7vgp/41.jpg?dl=0
https://www.dropbox.com/s/67gen5nioob01tr/42.jpg?dl=0
https://www.dropbox.com/s/teu0wstuxauuga7/43.jpg?dl=0
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