I can\'t figure out the second part to this problem. Can somebody help me? In th

Question

I can't figure out the second part to this problem. Can somebody help me?

In the figure the battery has a potential difference of V = 10.0 V and the five capacitors each have a capacitance of 12.0 muF. What is the charge on capacitor 1 and capacitor 2? Number *1 Units Number *2 Units significant digits are disabled; the tolerance is +/-2% significant digits are disabled; the tolerance is +/-2% significant digits not applicable; exact number, no tolerance significant digits are disabled; the tolerance is +/-2% significant digits are disabled; the tolerance is +/-2% significant digits are disabled; the tolerance is +/-2%

Explanation / Answer

remember these about Combination of capacitors

if C1 and C2 are the individual capacitor that re connected in series,

then their resultant capaciatnce 1/Cnet = 1/C1+1/C2 or Cnet   = C1C2/(C1+C2)

if c1 and C2 are connected in parallel, then their effective capacitancen is Cnet = C1+C2

also in sereis combination same amount of charge passes through each of the capacitiors

and in parallel combination, same PD (voltage) exists across each of the capacito

so here for C2,

C2 and C are in sereis, C'    = 12*12/(12+12) = 6 uF

this 6 uF is in parallel with 12 uF

so C'' = 12 + 6 = 18 uF

this 18 uF is in series with 12 uF

so Cnet = 18 *12/(18+12)

Cnet = 7.2uF

now use the relation Q = CV

so

Charge Q = 7.2 e-6 * 10

Q = 72 uC

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