THREE PART QUESTION: PART A: Given lambda = 604.8[nm], then what is 1 / lambda 2

Question

THREE PART QUESTION:

PART A: Given lambda = 604.8[nm], then what is 1 / lambda2? [nm-2]
(Report your answer in Scientific Notion 0.00E-00 with three significant figures, or N/A if there is no answer.)

PART B: Given lambda-2 = 2.73E-06[nm-2] and theta = 39.35[degrees], then what is the index of refraction to the nearest hundreths? (Take the phi in the equation for n in the manual to be 60 degrees.)

PART C: An angle marking is like a meter stick marking. The marking of 1.2m on a meter stick only means an object is 1.2m long if the object starts at zero meters. If it starts at 0.2 meters then the object is really 1.0 meters long. You will be making angle calculations from angle markings in a similar fashion.
Given a green marking of 223 degrees and a straight-on marking of 250 degrees, how much has the light bent?

Explanation / Answer

part A: 11/wavelength = 1/604.8 e-9

1/L = 1.653 e 6 m^-1

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apply the formula for refractive index as n = c/v = L/Lo

n = 2.73 e-6/(604.8 e-9)

n = 4.51

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