answer a b and c questions. A horizontal force of magnitude 35.0 U pushes a bloc

Question

answer a b and c questions.

A horizontal force of magnitude 35.0 U pushes a block of mass 4.00 kg across a floor where the coefficient of kinetic friction is mu k = 0.6. How much work is done by that applied force on the block-floor system when the block slides through a displacement of 3.00 m across the floor? During that displacement, the thermal energy of the block increases by 40.0 J. What is the increase in thermal energy of the floor? What is the increase in the kinetic energy of the block? WFa = F rightarrow a.d rightarrow = Fadcos theta Fad = 105J

Explanation / Answer

B. The thermal energy of the floor increases by the same amount, 40.0 J.   [ANSWER]

C.

delta KE = Work - Heat

Thus,

delta KE = 105 J - 40 J = 65 J   [ANSWER]

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