lens\'s help. 013 (part 1 of 4) 10.0 points An object is placed 10 m before a co

Question

lens's help.

013 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with focal length 4.7 m. Another concave lens is placed 13.8 m behind the first lens with a focal length -7.2 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer. 7.2 m 4.7 m fi f2 pl. 13.8 m 10 m 10 15 20 25 At what distance is the first image from the first lens Answer in units of m. 014 (part 2 of 4) 10.0 points What is the magnification of the first image? 015 (part 3 of 4) 10.0 points At what distance is the second image from the second lens? Answer in units of m. 016 (part 4 of 4) 10.0 points What is the magnification of the final image, when compared to the initial object?

Explanation / Answer

1) We have:

1/s + 1/s' = 1/f

1/10 + 1/s' = 1/4.7

solving we have: s' = 8.87 m

2) the magnification is:

m1 = -s'/s = -0.8867

3) for this case:

s2 = d- s' = 12.9

using:

1/s + 1/s' = 1/f

solving for s' we have:

s' = 4.90 cm

d) The magnification is:

m = -s'/s = 3.37

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