We have a small magnet with a magnetic moment of m = 0.1 Am2 (remember: magnetic

Question

We have a small magnet with a magnetic moment of m = 0.1 Am2 (remember: magnetic moment is defined as m = IA).

N = 100 circular loops of a single wire. A single loop has a radius of 10 cm.

The wire has a circular cross section with a 0.5 mm radius. The coiled wire is made of copper.

1) What is the total resistance of the total length of coiled wire? The magnet is dropped, north pole first, from a height of 2 meters above the coil. The coils are oriented so that the magnet should pass straight through the middle.

Explanation / Answer

Here ,

total length of copper wire , L = 100 * 2*pi*0.10

L = 62.82 m

Now, resistance of copper wire= resistivity * length /area

resistance of copper wire = 1.68 *10^-8 * 62.82 /(pi*0.0005^2)

resistance of copper wire= 1.344 Ohm

the resistance of copper wire is 1.344 Ohm

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.