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Three parallel wires that are each 600 m long and spaced 0.5 m apart, carry curr

ID: 1385227 • Letter: T

Question

Three parallel wires that are each 600 m long and spaced 0.5 m apart, carry currents and exert forces upon each other. Wire #1 and wire #2 are both fixed in position and cannot move. Wire #3 can move, but will break if it experiences a force of 15 N or more. Wire #1 is carrying a current of 240 A to the left and wire #2 is carrying a current of 140 A to the right.

A) What is the magnitude of the current that wire #3 must carry in order to experience enough force to break it?

B) Suppose the current in wire #1 is halved while the current in wire #2 remains the same. What is the magnitude of the current that wire #3 must carry in order to experience enough force to break it?

C) Suppose the current in wire #1 is suddenly shut off but the current in wire #2 remains the same. What is the magnitude of the current that wire #3 must carry in order to experience enough force to break it?

Explanation / Answer

wire 3 will experience forces in opp direction by 1 and 2

so, 4 pie * 10-7 i  ( 140/0.5 - 240/1) * 600 = 15 N

So, I = 500 A.

B) I =143 A

C) when no current in 1 , I = 7.11 A

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