A) Find the equivalent resistance of the circuit shown below between points A&B

Question

A) Find the equivalent resistance of the circuit shown below between points A&B

B) Find the equivalent capacitance of the circuit below points A & B

C) You charge the capacitors in the figure from part B so that the difference in electrical potential between points A & B is (delta)V= 10V. You then connect point 'A' of the capacitor circuit to point 'a' of the resistor circuit (in part A) and connect B to b, making a complete circuit. What would the initial current through the circuit, Io, be?

Explanation / Answer

remember these about Combination of Resistors

if R1 and R2 are the resistances connected in series then effective resiatcne Rnet = R1+R2

if R1 and R2 are connected in parallel, then 1/Rnet =1/R1 +1/R2 or Rnet =   R1R2/(R1+R2)

same current passes through each of the ressitor in series combination and

same votage passes through eacf of the resistor in parallel combination

apply ohms law V = iR

where V = volatge and i = current

so here 3k and 1.5 k are in series = 4.5 k ohms

2k and 5 k are in seres = 7 k ohms

4.5 k and 7 k are in paralell = 4.5 * 7/(4.5+7) = 2.74 k ohms

this 2.74 K ohms is in series with 1k ohms =    3.73 k ohms

this 3.74 k ohms is in parallel with 10 k ohms

so RNet between A and B = 3.74 * 10/(13.74)   = 2.72 k ohms

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remember these about Combination of capacitors

if C1 and C2 are the individual capacitor that re connected in series,

then their resultant capaciatnce 1/Cnet = 1/C1+1/C2 or Cnet   = C1C2/(C1+C2)

if c1 and C2 are connected in parallel, then their effective capacitancen is Cnet = C1+C2

also in sereis combination same amount of charge passes through each of the capacitiors

and in parallel combination, same PD (voltage) exists across each of the capacitor

B. 1uF and 2 uF are in parallel = 3 uF

3 uF is in sereis with 3uF and 2uF so

1/Cnet    = 1/3 + 1/3 + 1./2

Cnet = 0.857 uF

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part C:

ijn RC ckt

intial current i = V/R

i = 10/2720

i = 3.67 mA

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