A drug is tagged with 99 43 Tc. The atomic mass of Technetium-99 is 98.906254 am

Question

A drug is tagged with 99 43 Tc. The atomic mass of Technetium-99 is 98.906254 amu (a) Find total total binding energy of this isotope. (b) Find the binding energy per nucleon for this isotope. (c) The isotope radioactively decays into 99 44Ru. The atomic mass of Kuthenium-99 is 98.905939 amu. Calculate the binding energy of this isotope. (d) Find the binding energy per nucleon for Ru-99. (e) Compare the binding energy per nucleon for Ru-99 and Tc-99. Does it make sense that the Tc isotope, decayed into this Ru isotope? Does this decay happen spontaneously or does it require additional energy to occur?

Explanation / Answer

A) mass defect delta m = (43*1.007825) + ((99-43)*(1.008665))-98.906254

delta m = 0.915461 amu

BE = delta m*c^2 = 0.915461 amu*c^2
but 1 amu*c^2 = 931.5 MeV

BE = 0.915461*931.5 MeV = 852.75 MeV

B) BE per nucleon = BE/A = 852.75/99 = 8.613 MeV

C) delta m= (44*1.007825) + ((99-44)*(1.008665))-98.905939 = 0.914936 amu

BE = delta m*c^2 = 0.914936 amu*c^2 = 0.914936*931.5 MeV = 852.26 MeV

D) BE per nucleon = BE/A= 852.26/99 = 8.608 MeV

e) BE of Ru-99 is less than Tc-99

yes .thisdecay happen spontaneously

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