A crate of mass 10.2 kg is pulled up a rough incline no with an initial spend of

Question

A crate of mass 10.2 kg is pulled up a rough incline no with an initial spend of 1.44 m/s. The pulling force is 90 N parallel to the inline, which makes an angle of 20.6 degree horizontal. The coefficient of kinetic friction is 0.400, and the crate o pulled 5 04 m. How much work is done by the gravitational force on the crate? Determine the increase in internal energy of the crate-incline system owing to friction. How much work is done by the 90-N force on the crate? What is the change in kinetic energy of the crate? What is the speed of the crate after being pulled 5.04 M?

Explanation / Answer

You might have done small calculation mistakes in part a,b, and c.
d)
Net force acting on the crate

Fnet = 90 - m*g*sin(20.6) - mue_k*m*g*cos(20.6)

= 90 - 10.2*9.8*sin(20.6) - 0.4*10.2*9.8*cos(20.6)

= 17.4 N

Net workdone, Wnet = Fnet*d

= 17.4*5.04

= 87.7 J

According Work-Energy theorm,

change in kinetic energy = Wnet

= 87.70 J <<<<<<<<<<-------------------Answer

e) Apply

Wnet = 0.5*m*(v2^2-v1)^2

v2 = sqrt(v1^2 + 2*Wnet/m)

= sqrt(1.44^2 + 2*87.7/10.2)

= 4.39 m/s <<<<<<<<<<-------------------Answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.