A (static) mobile hangs as shown below. The rods are massless and have lengths a
ID: 1388686 • Letter: A
Question
A (static) mobile hangs as shown below. The rods are massless and have lengths as indicated. The mass of the ball at the bottom left is 1.0 kg. What is the mass of ball at the bottom left is 1.0 kg. what is the mass of ball1 (m1), ball 2 (m2) and the total mass mtot of the mobile? In Cavendish's experiment a 1560 N (350 lb) solid metal ball is brought near a 7.16 N (1.61 lb) ball. If their centers of mass are separated by 10.1 cm what gravitational attraction should Cavendish find using his torsion balance (G=6.66Times10-11N m2 / kg2)? If the initial distance between the balls in problem #6 is tripled to a final position then how will the final force of gravity Ff compare to the initial Fi?Explanation / Answer
Summing torques on the bar below,
1.0 kg (2.0 m) - m1 (6.0 m) = 0
Thus,
m1 = 0.3333 kg [answer]
Thus, the total mass of the bottom row is 1.3333 kg.
Summing force on the bar above,
1.3333 kg (2.0 m) - m2 (4.0 m) = 0
Thus,
m2 = 0.66667 kg [ANSWER]
Thus,
mtot = 1.0 kg + 0.3333 kg + 0.66667 kg = 2.00 kg [ANSWER]
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