xercise 15.40 A rope of length 1.41m is stretched between two supports with a te
ID: 1389151 • Letter: X
Question
xercise 15.40
A rope of length 1.41m is stretched between two supports with a tension that makes the transverse waves have a speed of 49.0m/s .
Part A
What is the wavelength of the fundamental harmonic?
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Part B
What is the frequency of the fundamental harmonic?
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Part C
What is the wavelength of the second overtone?
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Part D
What is the frequency of the second overtone?
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Part E
What is the wavelength of the fourth harmonic?
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Part F
What is the frequency of the fourth harmonic?
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xercise 15.40
A rope of length 1.41m is stretched between two supports with a tension that makes the transverse waves have a speed of 49.0m/s .
Part A
What is the wavelength of the fundamental harmonic?
SubmitHintsMy AnswersGive UpReview Part
Part B
What is the frequency of the fundamental harmonic?
? = mSubmitHintsMy AnswersGive UpReview Part
Part C
What is the wavelength of the second overtone?
f = HzSubmitHintsMy AnswersGive UpReview Part
Part D
What is the frequency of the second overtone?
? = mSubmitHintsMy AnswersGive UpReview Part
Part E
What is the wavelength of the fourth harmonic?
f = HzSubmitHintsMy AnswersGive UpReview Part
Part F
What is the frequency of the fourth harmonic?
? = mSubmitHintsMy AnswersGive UpReview Part
f = HzExplanation / Answer
A) Wavelenth of fundamental harmonic, lamda1 = 2*L
= 2*1.41
= 2.82 m
B) the frequency of the fundamental harmonic, f1 = v/lamda1
= 49/2.82
= 17.4 Hz
C)What is the wavelength of the second overtone, lamda3 = 2*L/3
= 2*1.41/3
= 0.94 m
d) the frequency of the second overtone, f3 = v/lamda3
= 49/0.94
= 52.12 Hz
e) What is the wavelength of the fourth harmonic, lamda4 = 2*L/4
= 2*1.41/4
= 0.705 m
f) the frequency of the second overtone, f3 = v/lamda3
= 49/0.705
= 69.5 Hz
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