Two particles having charges of 0.526nC and 18.9nC are separated by a distance o

ID: 1390654 • Letter: T

Question

Two particles having charges of 0.526nC and 18.9nC are separated by a distance of 1.19m .

Part A

At what point along the line connecting the two charges is the net electric field due to the two charges equal to zero?

0.170

Correct

Part B

Where would the net electric field be zero if one of the charges were negative?

Enter your answer as a distance from the charge initially equal 0.526nC .

I have attempted part B over and over and I am not sure where I am going wrong. Please help!

Two particles having charges of 0.526nC and 18.9nC are separated by a distance of 1.19m .

Part A

At what point along the line connecting the two charges is the net electric field due to the two charges equal to zero?

The electric field is zero at a point =

0.170

m from 0.526nC .

Correct

Part B

Where would the net electric field be zero if one of the charges were negative?

Enter your answer as a distance from the charge initially equal 0.526nC .

I have attempted part B over and over and I am not sure where I am going wrong. Please help!

here ,

for one of the charges as negative ,

let the field is zero at x m from 0.526 nC

Now, for field to zero ,

k*0.526/x^2 = k*18.9/(x + 1.19)^2

now,

0.526/x^2 = 18.9/(x + 1.19)^2

solving for x

x = 0.238 m

the distance of the point is 0.238 from 0.526 nC

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.