1) A doubly ionized carbon atom (with charge 2e) is located at the origin of the

Question

1) A doubly ionized carbon atom (with charge 2e) is located at the origin of the x axis, and an electron (with charge -e) is placed at x = 3.51 cm. There is one location along the x axis at which the electric field is zero. Give the x coordinate of this point in ? cm...... 2) Assume that the potential is defined to be zero infinitely far away from the particles. Unlike the electric field, the potential will be zero at multiple points near the particles. Find the two points along the x axis at which the potential is zero, and express their locations along the x axis in cm, starting with the point which is farther away from the origin.

Explanation / Answer

have to be on the far side of the elctron so e pulls and carbon atom pushes

k 2e/x^2 = k e/(x - 3.51)^2
2(x-3.51)^2 = x^2
x=11.984 cm

b)
now Ve = V carbon
case 1:
k 2e/x= k e/(x - 3.51)
2(x - 3.51) = x
x = 2*3.51 = 7.02 cm

case 2:
k 2e/x= k e/(-x +3.51)
-2x + 7.02 = x
x = 7.02/3=2.34 cm

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