Consider a resistive circuit with a 24 V power supply and 3 resistors. Two of th

Question

Consider a resistive circuit with a 24 V power supply and 3 resistors. Two of the resistors are in parallel at 120 ohms and 240 ohms and the third resistor is in series. The internal resistance of the battery is 1.6 ohms.
*Find the equivalent resistance of the circuit & Find the current through the 240 ohm resistor. Consider a resistive circuit with a 24 V power supply and 3 resistors. Two of the resistors are in parallel at 120 ohms and 240 ohms and the third resistor is in series. The internal resistance of the battery is 1.6 ohms.
*Find the equivalent resistance of the circuit & Find the current through the 240 ohm resistor.
*Find the equivalent resistance of the circuit & Find the current through the 240 ohm resistor.

Explanation / Answer

Given that,

V = 24 Volts; r(internal) = 1.6 Ohms

(The vale of third resistance is not provided, I am taking the following assumptions here)

Assuming the resistance of resisrots connected in parallel = R1 = R2 = 120 Ohms

R(eq12) = R1xR2 / R1+R2 = 120 x 120 / 120 + 120 = 60 Ohm

R3 = 240 Ohms

The equivalent resistance of the circuit will be then

R(eq) = R(eq12) + R3 = 60+240 = 300 Ohm

We know that, V = IR , I = V/R = 24/300 = 0.08 A

I = 0.08 A

We know that the terminal voltage of the batter with r as internal resistance is given by

V(t) = Vb - ir(internal) = 24 - 0.08 x 1.6 = 23.87 V

The current through R3 = 240 Ohm will be given by

I(R3) = 23.87/240 = 0.0994 Amperes

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