Please show all your work! A series RLC circuit is driven by an AC voltage sourc

Question

Please show all your work!

A series RLC circuit is driven by an AC voltage source (Delta Vrms = 30.0V) at 796 Hz. The circuit has a 150 Ohm resistor and a 20.0 mH inductor. 16 points. a) Find the capacitance needed for the circuit to be at resonance. b) Find the maximum current and average power of the circuit. c) While the voltage source continues to drive the circuit at 796 Hz, a second capacitor equal to the first is placed in parallel with it. Find the maximum current, phase angle and average power.

Explanation / Answer

PART-A:-
Resonance will occour when Omega= 1/Sqrt(L*C) where Omega= 2*pi* frequency.
So, Sqrt(20C* 10^-3)= 1/5001.4
So, C=1/500 *1000= 2F
So, capacitance= 2F.

PART-B:-

Maximum current= 30/R= 0.2 A.
Power= V^2/R= 6W.

PART-C:-

Maximum current= V/Sqrt(R^2+(Omega*L-1/(Omega*2C))^2)
Put the values and get the result.
Power= V^2/Sqrt(R^2+(Omega*L-1/(Omega*2C))^2)
Phase angle= Tan inverse[(Omega*L-1/(Omega*2C)/R)]

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.