please show work so I can understand A nonconducting solid sphere of radius 2.60

Question

please show work so I can understand

A nonconducting solid sphere of radius 2.60 cm carries a uniformly distributed positive charge of 6.80×10-9 C. Calculate the magnitude of the electric field at a point 1.80 cm away from the center of the sphere.
This distance is still within the sphere. You have to integrate the charge up to this distance.Incorrect.Tries 2/10Previous Tries
Calculate the magnitude of the electric field at a point 3.90 cm away from the center of the sphere.
Tries 0/10Assume that the sphere is conducting. Calculate the magnitude of the electric field at a point 1.80 cm away from the center of the sphere.
Tries 0/10Calculate the magnitude of the electric field for the conducting sphere at a point 3.90 cm away from the center of the sphere.

Explanation / Answer

E = k q(r^3 / R^3) / r^2 = kqr / R^3
Where r= distance at which electric field is to be measured & R= radius of sphere.

In part 2, we have to calculate electric field at the point which is outside the sphere. Electric field at the point which is outside the sphere is:-
E= kq / r^2 where r= distance of the point outside the sphere.

And value of k is taken as 9* 10^9 N-m^2/s^2

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