In the accompanying diagram, a pair of conducting rails supports the red bar, le
ID: 1394005 • Letter: I
Question
In the accompanying diagram, a pair of conducting rails supports the red bar, length l = 40 cm, which is pulled downward by gravity at a constant terminal speed of vT = 5 m/s. If there is a magnetic field out of the page with a strength B0 = 1 T, and the resistance is R = 2 ohm, what are the induced emf e0 and the induced current I0 in the loop ( both magnitude and direction)? What is the power PR dissipated by the resistor? What is the magnetic force FB on the red bar (magnitude and direction)? What is the mass M of the bar needed to maintain this terminal speed?Explanation / Answer
here ,
a)
induced EMF = B*v*L
induced EMF = 1* 5 * 0.40
induced EMF = 2 V
the induced emf is 2 V
induced current = induced EMF/R
induced current = 2/2
induced current = 1 A
the induced current is 1 A
as the flux through the loop is increasing , according to Lenz law ,
the direction of induced current is CLOCKWISE
b)
power = I^2 * R
Power = 1^2 * 2
Power = 2 W
the power dissipated is 2 W
c)
Fa = B*I*L
Fa = 1 * (1) * 0.40
Fa = 0.40 N in the direction oposite to velocity
d)
for terminal speed ,
Fa = m*g
0.40 = m*9.8
m = 0.0408 Kg = 40.8 gm
the mass of rod is 40.8 gm
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