A cart carrying a vertical missile launcher moves horizontally at a constant vel

Question

A cart carrying a vertical missile launcher moves horizontally at a constant velocity of 30.0m/s to the right. It launches a rocket vertically upward. The missile has an initial vertical velocity of 40.0m/s relative to the cart.(Figure 1) How high does the rocket go?

2)

How far does the cart travel while the rocket is in the air?

3)Where does the rocket land relative to the cart?

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A tennis player hits a ball at ground level, giving it an initial velocity of 25.0m/s at 60.0? above the horizontal.

1) How high above the ground does the ball go?

2) How long does it take the ball to reach its maximum height?

3   What is the ball's velocity at its highest point?

4) What is the ball's acceleration at its highest point?

5) For how long a time is the ball in the air?

6) When this ball lands on the court, how far is it from the place where it was hit?

Explanation / Answer

The cart's horizontal speed doesn't enter into calculations about vertical flight.

The height is given by s in
Vf is final velocity, zero at the max height;

Vi is initial velocity,

a = -g (minus because Vi is upward and g is downward).

Vf2 = Vi2 + 2*a*s

0=402+2as

solving we get,s=81.6m

b) Time missile is in the air i.e time to return to the launch height = t,

displacement, d = 0
d = vit - 1/2gt

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